Solution Prob. 2–4/5 Engineering Mechanics Statics R.C Hibbeler 14th

The vertical force F acts downward at A on the twomembered frame. Determine the magnitudes of the two components of F directed along the axes of AB an

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Prob. 2-4/5 R.C Hibbeler 14th

R.C Hibbeler 14th

2–4. The vertical force F acts downward at A on the twomembered frame. Determine the magnitudes of the two components of F directed along the axes of AB and AC. Set F = 500 N.

Solution

Diagram Benda Bebas (DBB)

Ans.

Parallelogram Law: The parallelogram law of addition is shown in Fig. a.
Trigonometry: Using the law of sines (Fig. b), we have

Ans:

FAB = 448 N

FAC = 366 N

2–5. Solve Prob. 2–4 with F = 350 lb.

prob. 2-5 R.C Hibbeler 14th

Solution

Diagram Benda Bebas (DBB)

prob. 2-5 R.C Hibbeler 14th

Ans

Parallelogram Law: The parallelogram law of addition is shown in Fig. a.
Trigonometry: Using the law of sines (Fig. b), we have

prob. 2-5 R.C Hibbeler 14th

Ans:

FAB = 314 N

FAC = 256 N

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